Is an element on the visible screen

A number of times I have been on a website where clicking a link goes to a specific page with a specific element at the top of the page. For example, I am reading an article and it quotes a book. The quote is actually from page 17, paragraph 2, first sentence. So when I click the link to the article it should take me to page 17, paragraph 2, first sentence.

So how would you automate testing this?

The simple answer would be to find the WebElement which is expected to be at the top of the page. This is the easy part. Then you need to see if the WebElement is on the visible screen. If you click it, WebDriver will scroll it into view. This is not what we want.

So what do we do? The answer is find out the size of the visible window then see if the bottom-right corner of the WebElement is inside that dimension. So here is the code for that:

  private boolean isWebElementVisible(WebElement w) {
    Dimension weD = w.getSize();
    Point weP = w.getLocation();
    Dimension d = driver.manage().window().getSize();

    int x = d.getWidth();
    int y = d.getHeight();
    int x2 = weD.getWidth() + weP.getX();
    int y2 = weD.getHeight() + weP.getY();

    return x2 <= x && y2 <= y;
  }

This will tell me of the element is on the visible window. If the element is not on the visible window it will return false. If the element is on the visible window it will return true... well almost. Unfortunately, you can get the size of the browser window but you really want the size of the chrome, inside the window. So if the window dimension is 1024x768 it is really telling you how big the OUTSIDE of the window is and not the inside. If the element is located at 1024x768 it is really off the visible window. For example, on my Google Chrome the tabs/title is 22px high. So the visible screen would really be 768 - 22 or 746px.

So this is a close approximation but there is a small chance of the element being just off the bottom of the window and still return true. If you are running driver.manage().window().maximize() the odds that something is going to be off the bottom of the visible window is small enough that it is not worth worrying about. Add to that we would hopefully be manually testing the area occasionally during exploratory testing and the risk should be acceptable.

There is another problems with this. We aren't actually checking that the upper-left corner of the element is at the top of the screen. You might think, why not just check that the element we are looking for is at position (0, 0)? The reason for not checking this is because the element might not be exactly at (0, 0). If the screen is large enough for 20 elements, the page only has 4 elements and the element we are looking for is at the second position, it will be impossible for the element we are looking for to scroll. So it will be below (0, 0) but still on the visible window.

A good example if this code would be:

    driver.get("http://www.w3schools.com");
    WebElement we = driver.findElement(By.cssSelector("#gsc-i-id1"));
    assertTrue(isWebElementVisible(we));
    WebElement we2 = driver.findElement(By.cssSelector("#footer"));
    assertFalse(isWebElementVisible(we2));

This will go to www.w3schools.com, find the Google search input at the top of the page, confirm it is visible. Then it will find the footer at the bottom of the page and confirm it is not visible.